栈stack
225. Implement Stack using Queues Easy
232. Implement Queue using Stacks Easy
这两道提互为实现,刚好放到一起学习。既然两种数据结构可以互相实现,可以看看有什么相似之处。
队列queue:先进先出FIFO;栈Stack 后进先出LIFO。只需要保证添加数据时排好顺序即可。
Implement the following operations of a stack using queues.
- push(x) – Push element x onto stack.
- pop() – Removes the element on top of the stack.
- top() – Get the top element.
- empty() – Return whether the stack is empty.
Example:
MyStack stack = new MyStack();
stack.push(1);
stack.push(2);
stack.top(); // returns 2
stack.pop(); // returns 2
stack.empty(); // returns false\
Notes:
- You must use only standard operations of a queue – which means only
push to back
,peek/pop from front
,size
, andis empty
operations are valid. - Depending on your language, queue may not be supported natively. You may simulate a queue by using a list or deque (double-ended queue), as long as you use only standard operations of a queue.
- You may assume that all operations are valid (for example, no pop or top operations will be called on an empty stack).
实现好第一个方法即可。
private Queue<Integer> queue = new LinkedList<>();
public void push(int x) {
//重新放到第一个位置
queue.add(x);
// 移动后面的值
for (int i=1; i<queue.size(); i++) {
queue.add(queue.remove());
}
}
public int pop() {
return queue.remove();
}
public int top() {
return queue.peek();
}
public boolean empty() {
return queue.isEmpty();
}
Implement the following operations of a queue using stacks.
- push(x) – Push element x to the back of queue.
- pop() – Removes the element from in front of queue.
- peek() – Get the front element.
- empty() – Return whether the queue is empty.
Example:
MyQueue queue = new MyQueue();
queue.push(1);
queue.push(2);
queue.peek(); // returns 1
queue.pop(); // returns 1
queue.empty(); // returns false
Notes:
- You must use only standard operations of a stack – which means only
push to top
,peek/pop from top
,size
, andis empty
operations are valid. - Depending on your language, stack may not be supported natively. You may simulate a stack by using a list or deque (double-ended queue), as long as you use only standard operations of a stack.
- You may assume that all operations are valid (for example, no pop or peek operations will be called on an empty queue).
相同的地方:只需要实现好push方法即可。
//转换位置:新添加的x要保证最后出来
public void push(int x) {
Stack<Integer> temp = new Stack<>();
while(!stack.empty()){
temp.push(stack.pop());
}
stack.push(x);
while(!temp.empty()){
stack.push(temp.pop());
}
}
/** Removes the element from in front of queue and returns that element. */
public int pop() {
return stack.pop();
}
/** Get the front element. */
public int peek() {
return stack.peek();
}
/** Returns whether the queue is empty. */
public boolean empty() {
return stack.isEmpty();
}
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